4x^2+9x-56=7

Solution for 4x^2+9x-56=7 equation:

4x^2+9x-56=7

We move all terms to the left:

4x^2+9x-56-(7)=0

We add all the numbers together, and all the variables

4x^2+9x-63=0

a = 4; b = 9; c = -63;
Δ = b2-4ac
Δ = 92-4·4·(-63)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-33}{2*4}=\frac{-42}{8}
=-5+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+33}{2*4}=\frac{24}{8}
=3
$